If (A-B)^2 =64 And Ab =3, A^2 + B^2 =?
If (a-b)^2 =64 and ab =3, a^2 + b^2 =?
(a - b)² = 64
Simplify it first
a² - 2ab + b² = 64
a = 3 then we will just substitute it
a² - 2(3) + b² = 64
a² - 6 + b² = 64
a² + b² = 64 + 6
a² + b² = 70
Answer:
If (a-b)^2 =64 and ab =3, a^2 + b^2 =?
(a - b)² = 64
Simplify it first
a² - 2ab + b² = 64
a = 3 then we will just substitute it
a² - 2(3) + b² = 64
a² - 6 + b² = 64
a² + b² = 64 + 6
a² + b² = 70
Answer:
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